Current Electricity Charging Discharging Of Capacitors Question 58
Question: In an electroplating experiment, m gm of silver is deposited when 4 ampere of current flows for 2 minute. The amount (in gm) of silver deposited by 6 ampere of current for 40 second will be
[MNR 1991; UPSEAT 2000; MP PET 2002; Pb. PET 2004; Orissa JEE 2005]
Options:
A) 4 m
B) $ m/2 $
C) $ m/4 $
D) 2 m
Show Answer
Answer:
Correct Answer: B
Solution:
By Faraday’s law, $ m\propto i,t. $ \ $ \frac{m _{1}}{m _{2}}=\frac{i _{1}t _{1}}{i _{2}t _{2}} $
Therefore $ \frac{m}{m _{2}}=\frac{4\times 120}{6\times 40} $
Therefore $ m _{2}=\frac{m}{2} $
BETA
