Current Electricity Charging Discharging Of Capacitors Question 580
By a cell a current of 0.9 A flows through a 2 ohm resistor and 0.3 A through a 7 ohm resistor. The internal resistance of the cell is
[KCET 2003]
Options:
A) $ 0.5,\Omega $
B) $ 1.0,\Omega $
C) $ 1.2,\Omega $
D) $ 2.0,\Omega $
Show Answer
Answer:
Correct Answer: A
Solution:
0.9 (2 + r) = 0.3 (7 + r)
Therefore 6 + 3r = 7 + r
Therefore r = 0.5 W
BETA
