Current Electricity Charging Discharging Of Capacitors Question 582
Question: A cell of e.m.f. $ E $ is connected with an external resistance $ R $ , then p.d. across cell is $ V $ . The internal resistance of cell will be
[MNR 1987; Kerala PMT 2002; MP PMT 2002]
Options:
A) $ \frac{(E-V)R}{E} $
B) $ \frac{(E-V)R}{V} $
C) $ \frac{(V-E)R}{V} $
D) $ \frac{(V-E)R}{E} $
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Answer:
Correct Answer: B
Solution:
Let the current in the circuit $ =i=\frac{V}{R} $ Across the cell, $ E=V+ir $
Therefore $ r=\frac{E-V}{i}=\frac{E-V}{V/R}=( \frac{E-V}{V} ),R $
BETA
