Current Electricity Charging Discharging Of Capacitors Question 147
Question: In the circuit shown here, E1 = E2 = E3 = 2 V and R1 = R2 = 4 ohms. The current flowing between points A and B through battery E2 is
[MP PET 2001]
Options:
A) Zero
B) 2 amp from A to B
C) 2 amp from B to A
D) None of the above
Show Answer
Answer:
Correct Answer: B
Solution:
The given circuit can be redrawn $ E _{eq}=\frac{E _{1}R _{2}+E _{2}R _{1}}{R _{1}+R _{2}}=\frac{2\times 4+2\times 4}{4+4}=4V $ and $ R _{eq}=\frac{4}{2}=2\Omega $ . Current $ i=\frac{4}{2}=2A $ from A to B through E2
BETA
