Current Electricity Charging Discharging Of Capacitors Question 593
Question: A primary cell has an e.m.f. of 1.5 volts, when short-circuited it gives a current of 3 amperes. The internal resistance of the cell is
[CPMT 1976, 83]
Options:
A) 4.5 $ ohm $
B) 2 $ ohm $
C) 0.5 $ ohm $
D) 1/4.5 $ ohm $
Show Answer
Answer:
Correct Answer: C
Solution:
Short circuit current $ i _{SC}=\frac{E}{r} $
Therefore $ 3=\frac{1.5}{r} $
Therefore $ r=0.5\Omega $
BETA
