Current Electricity Charging Discharging Of Capacitors Question 594
Question: A 50V battery is connected across a 10 ohm resistor. The current is 4.5 amperes. The internal resistance of the battery is
[CPMT 1985; BHU 1997; Pb. PMT 2001]
Options:
A) Zero
B) 0.5 ohm
C) 1.1 ohm
D) 5.0 ohm
Show Answer
Answer:
Correct Answer: C
Solution:
$ i=\frac{50}{R+r} $
Therefore $ r=\frac{50}{4.5}-10=\frac{5}{4.5}=1.1\Omega $
BETA
