Current Electricity Charging Discharging Of Capacitors Question 6
Question: Assertion : An electric bulb is first connected to a dc source and then to a ac source having the same brightness in both the cases. Reason : The peak value of voltage for an A.C. source is $ \sqrt{2} $ times the root mean square voltage.
Options:
A) If both assertion and reason are true and the reason is the correct explanation of the assertion.
B) If both assertion and reason are true but reason is not the correct explanation of the assertion.
C) If assertion is true but reason is false.
D) If the assertion and reason both are false.
E) If assertion is false but reason is true.
Show Answer
Answer:
Correct Answer: E
Solution:
Voltage of dc source is constant but in ac, peak value of voltage is $ \sqrt{2} $ times the rms. voltage. Hence bulb will glow with more brightness when connected to an ac source of the same voltage.
BETA
