Current Electricity Charging Discharging Of Capacitors Question 61
Question: A steady current of 5 amps is maintained for 45 mins. During this time it deposits 4.572 gms of zinc at the cathode of a voltameter. E.C.E. of zinc is
[MP PET 1994]
Options:
A) $ 3.387\times {{10}^{-4}}gm/C $
B) $ 3.387\times {{10}^{-4}}C/gm $
C) $ 3.384\times {{10}^{-3}}gm/C $
D) $ 3.394\times {{10}^{-3}}C/gm $
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Answer:
Correct Answer: A
Solution:
$ m=Zi,t $
Therefore $ Z=\frac{m}{i,t} $
$ =\frac{4.572}{5\times 45\times 60}=3.387\times {{10}^{-4}},gm/C $
BETA
