Current Electricity Charging Discharging Of Capacitors Question 611
Question: Consider the circuit given here with the following parameters E.M.F. of the cell = 12 V. Internal resistance of the cell $ =2,\Omega $ . Resistance $ R=4,\Omega $ Which one of the following statements in true
Options:
A) Rate of energy loss in the source is = 8 W
B) Rate of energy conversion in the source is 16 W
C) Power output in is = 8 W
D) Potential drop across R is = 16 V
Show Answer
Answer:
Correct Answer: A
Solution:
$ i=\frac{12}{(4+2)}=2A $ Energy loss inside the source $ =i^{2}r $
$ ={{(2)}^{2}}\times 2=8W $
BETA
