Current Electricity Charging Discharging Of Capacitors Question 613
Question: 100 cells each of e.m.f. 5 V and internal resistance 1 ohm are to be arranged so as to produce maximum current in a 25 ohms resistance. Each row is to contain equal number of cells. The number of rows should be
[MP PMT 1997]
Options:
2
4
5
10
Show Answer
Answer:
Correct Answer: A
Solution:
If m = Number of rows and n = Number of cells in a row Then m × n = 100 …..(i) Also condition of maximum current is $ R=\frac{nr}{m} $
Therefore $ 25=\frac{1\times n}{m} $
Therefore n = 25 m …..(ii) On solving (i) and (ii) m = 25
BETA
