Current Electricity Charging Discharging Of Capacitors Question 623
Question: For driving a current of 2 A for 6 minutes in a circuit, 1000 J of work is to be done. The e.m.f. of the source in the circuit is
[CPMT 1999]
Options:
A) 1.38 V
B) 1.68 V
C) 2.04 V
D) 3.10 V
Show Answer
Answer:
Correct Answer: A
Solution:
$ P=\frac{W}{t}=Vi $
Therefore $ V=\frac{W}{it}=\frac{1000}{2\times 6\times 60}=1.38,V $
BETA
