Current Electricity Charging Discharging Of Capacitors Question 624
Question: Two batteries of e.m.f. 4V and 8 V with internal resistances 1 W and 2 W are connected in a circuit with a resistance of 9 W as shown in figure. The current and potential difference between the points P and Q are
[AFMC 1999]
Options:
A) $ \frac{1}{3}A\text{and },3V $
B) $ \frac{1}{6}A\text{and},4V $
C) $ \frac{1}{9}A\text{and},\text{ 9}V $
D) $ \frac{1}{2}A\text{and}12V $
Show Answer
Answer:
Correct Answer: A
Solution:
Applying Kirchoff’s voltage law in the given loop. $ -2i+8-4-1\times i-9i=0 $
Therefore $ i=\frac{1}{3}A $ Potential difference across PQ $ =\frac{1}{3}\times 9=3V $
BETA
