Current Electricity Charging Discharging Of Capacitors Question 630
Question: In the given circuit the current I1 is
[DCE 2000]
Options:
A) 0.4 A
B) ? 0.4 A
C) 0.8 A
D) ? 0.8 A
Show Answer
Answer:
Correct Answer: B
Solution:
The circuit can be simplified as follows Applying KCL at junction A $ i _{3}=i _{1}+i _{2} $ .?.(i) Applying Kirchoff’s voltage law for the loop ABCDA $ -30i _{1}-40i _{3}+40=0 $
$ \Rightarrow -30i _{1}-40(i _{1}+i _{2})+40=0 $
$ \Rightarrow ,7i _{1}+4i _{2}=4 $ .?.(ii) Applying Kirchoff’s voltage law for the loop ADEFA. $ -40i _{2}-40i _{3}+80+40=0 $
$ \Rightarrow ,-40i _{2}-40(i _{1}+i _{2})=-120 $
$ \Rightarrow i _{1}+2i _{2}=3, $ ??.(iii) On solving equation (ii) and (iii) $ i _{1}=-0.4A $ .
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