Current Electricity Charging Discharging Of Capacitors Question 231
Question: In the Wheatstone’s bridge (shown in figure) $ X=Y $ and $ A>B $ . The direction of the current between ab will be
Options:
A) From a to b
B) From b to a
C) From b to a through c
D) From a to b through c
Show Answer
Answer:
Correct Answer: B
Solution:
In the part c b d, $ V _{c}-V _{b}=V _{b}-V _{d} $
Therefore $ V _{b}=\frac{V _{c}+V _{d}}{2} $ In the part c a d $ V _{c}-V _{a}>V _{a}-V _{d} $
Therefore $ \frac{V _{c}+V _{d}}{2}>V _{a} $
Therefore $ V _{b}>V _{a} $
BETA
