Current Electricity Charging Discharging Of Capacitors Question 637
Question: How much work is required to carry a 6 mC charge from the negative terminal to the positive terminal of a 9 V battery
[KCET (Med.) 2001]
Options:
A) 54 × $ {{10}^{-3}} $ J
B) 54 × $ {{10}^{-6}} $ J
C) 54 × $ {{10}^{-9}}J $
D) 54 × $ {{10}^{-12}} $ J
Show Answer
Answer:
Correct Answer: B
Solution:
$ W=qV=6\times {{10}^{-6}}\times 9=54\times {{10}^{-6}}J $ .
BETA
