Current Electricity Charging Discharging Of Capacitors Question 64
Question: Two electrolytic cells containing $ CuSO _{4} $ and $ AgNO _{3} $ respectively are connected in series and a current is passed through them until 1 mg of copper is deposited in the first cell. The amount of silver deposited in the second cell during this time is approximately
[Atomic weights of copper and silver are respectively 63.57 and 107.88] [MP PMT 1996]
Options:
A) 1.7 mg
B) 3.4 mg
C) 5.1 mg
D) 6.8 mg
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{m _{1}}{m _{2}}=\frac{E _{1}}{E _{2}} $ (By faraday law for same current and time) Where E1 and E2 are the chemical equivalents and m1 and m2 are the masses of copper and silver respectively. $ E=\frac{\text{Atomic weight}}{\text{Valency}} $ . $ E _{1}=\frac{63.57}{2}=31.79 $ and $ E _{2}=\frac{107.88}{1}=107.88 $ \ $ \frac{1,mg}{m _{2}}=\frac{31.79}{107.88} $
Therefore $ m _{2}=\frac{107.88}{31.79}mg=3.4,mg $
BETA
