Current Electricity Charging Discharging Of Capacitors Question 648
Question: Two batteries, one of emf 18 volts and internal resistance $ 2\Omega $ and the other of emf 12 volt and internal resistance $ 1\Omega $ , are connected as shown. The voltmeter $ V $ will record a reading of
[CBSE PMT 2005]
Options:
A) 15 volt
B) 30 volt
C) 14 volt
D) 18 volt
Show Answer
Answer:
Correct Answer: C
Solution:
Reading of voltmeter $ =E _{eq}=\frac{E _{1}r _{2}+E _{2}r _{1}}{r _{1}+r _{2}}=\frac{18\times 1+12\times 2}{1+2}=14V $
BETA
