Current Electricity Charging Discharging Of Capacitors Question 154
Question: In the given circuit, it is observed that the current I is independent of the value of the resistance R6. Then the resistance values must satisfy
[IIT-JEE (Screening) 2001]
Options:
A) $ R _{1}R _{2}R _{5}=R _{3}R _{4}R _{6} $
B) $ \frac{1}{R _{5}}+\frac{1}{R _{6}} $ $ =\frac{1}{R _{1}+R _{2}}+\frac{1}{R _{3}+R _{4}} $
C) $ R _{1}R _{4}=R _{2}R _{3} $
D) $ R _{1}R _{3}=R _{2}R _{4}=R _{5}R _{6} $
Show Answer
Answer:
Correct Answer: C
Solution:
As I is independent of $ R _{6}, $ no current flows through $ R _{6} $ this requires that the junction of $ R _{1} $ and $ R _{2} $ is at the same potential as the junction of $ R _{3} $ and $ R _{4} $ . This must satisfy the condition $ \frac{R _{1}}{R _{2}}=\frac{R _{3}}{R _{4}}, $ as in the Wheatstone bridge.
BETA
