Current Electricity Charging Discharging Of Capacitors Question 233
Question: The resistance of a galvanometer is 50 ohms and the current required to give full scale deflection is $ 100,\mu A $ . In order to convert it into an ammeter, reading upto 10A, it is necessary to put a resistance of
[MP PMT 1997; AIIMS 1999]
Options:
A) $ 5\times {{10}^{-3}},\Omega $ in parallel
B) $ 5\times {{10}^{-4}},\Omega $ in parallel
C) $ 10^{5},\Omega $ in series
D) $ 99,950,\Omega $ in series
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Answer:
Correct Answer: B
Solution:
Resistance in parallel $ S=\frac{Gi _{g}}{i-i _{g}}=\frac{50\times 100\times {{10}^{-6}}}{(10-100\times {{10}^{-6}})} $
Therefore $ S=5\times {{10}^{-4}},\Omega $