Current Electricity Charging Discharging Of Capacitors Question 664
Question: In order to determine the e.m.f. of a storage battery it was connected in series with a standard cell (both are adding) in a certain circuit and a current $ I _{1} $ was obtained. When polarity of the standard cell is reversed, a current $ I _{2} $ was obtained in the same direction as that of $ I _{1} $ what is the e.m.f. $ {\varepsilon _{1}} $ of the storage battery? The e.m.f. of the standard cell is $ {\varepsilon _{2}} $ .
Options:
A) $ {\varepsilon _{1}}=\frac{I _{1}+I _{2}}{I _{1}-I _{2}}{\varepsilon _{2}} $
B) $ {\varepsilon _{1}}=\frac{I _{1}+I _{2}}{I _{2}-I _{1}}{\varepsilon _{2}} $
C) $ {\varepsilon _{1}}=\frac{I _{1}-I _{2}}{I _{1}+I _{2}}{\varepsilon _{2}} $
D) $ {\varepsilon _{1}}=\frac{I _{2}-I _{1}}{I _{1}+I _{2}}{\varepsilon _{2}} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Dividing $ {\varepsilon _{1}}=( \frac{I _{1}+I _{2}}{I _{1}-I _{2}} ){\varepsilon _{2}} $
BETA
