Current Electricity Charging Discharging Of Capacitors Question 669
Question: For a cell, a graph is plotted between the potential Difference V across the terminals of the cell and the current $ I $ drawn from the cell (see figure). The emf and the internal resistance of the cell are E and r respectively. Then
Options:
A) $ E=2V,,r=0.5,\Omega $
B) $ E=2V,,r=0.4,\Omega $
C) $ E>2V,,r=0.5,\Omega $
D) $ E>2V,,r=0.4,\Omega $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] V=E-ir. When i=0, the potential reading is 2 V. hence emf is 2V. When V=0, i=5A. This gives $ r=0.4\Omega $
BETA
