Current Electricity Charging Discharging Of Capacitors Question 67
Question: If nearly $ 10^{5} $ coulomb liberate 1 gm equivalent of aluminium, then the amount of aluminium (equivalent weight 9) deposited through electrolysis in 20 minutes by a current of 50 amp will be
[CBSE PMT 1998]
Options:
A) 0.6 gm
B) 0.09 gm
C) 5.4 gm
D) 10.8 gm
Show Answer
Answer:
Correct Answer: C
Solution:
$ m=Zi,t $ or $ m\propto i,t $ \ $ \frac{m _{1}}{m _{2}}=\frac{i _{1}t _{1}}{i _{2}t _{2}} $
Therefore $ \frac{9}{m _{2}}=\frac{10^{5}}{50\times 20\times 60} $
Therefore $ m _{2}=5.4,gm $
BETA
