Current Electricity Charging Discharging Of Capacitors Question 191
Question: $ 50,\Omega $ and $ 100,\Omega $ resistors are connected in series. This connection is connected with a battery of 2.4 volts. When a voltmeter of $ 100,\Omega $ resistance is connected across $ 100,\Omega $ resistor, then the reading of the voltmeter will be
[MP PMT 1985]
Options:
A) 1.6 V
B) 1.0 V
C) 1.2 V
D) 2.0 V
Show Answer
Answer:
Correct Answer: C
Solution:
Equivalent resistance of the circuit $ R _{eq}=100\Omega $ current through the circuit $ i=\frac{2.4}{100}A $ P.D. across combination of voltmeter and 100 W resistance $ =\frac{2.4}{100}\times 50=1.2V $ Since the voltmeter and 100 W resistance are in parallel, so the voltmeter reads the same value i.e. 1.2V.
BETA
