Current Electricity Charging Discharging Of Capacitors Question 236
Question: If only 2% of the main current is to be passed through a galvanometer of resistance G, then the resistance of shunt will be
[MP PMT/PET 1998]
Options:
A) $ \frac{G}{50} $
B) $ \frac{G}{49} $
C) $ 50,G $
D) $ 49,G $
Show Answer
Answer:
Correct Answer: B
Solution:
$ i _{g}=2% $ of $ i=\frac{i}{50} $
Therefore $ S=\frac{G}{(n-1)}=\frac{G}{(50-1)}=\frac{G}{49} $
BETA
