Current Electricity Charging Discharging Of Capacitors Question 71
Question: The value of current required to deposit 0.972 gm of chromium in 3 hours if the E.C.E. of chromium is 0.00018 gm per coulomb, is
[SCRA 1994]
Options:
A) 1 amp
B) 1.5 amp
C) 0.5 amp
D) 2 amp
Show Answer
Answer:
Correct Answer: C
Solution:
$ i=\frac{m}{Zt}=\frac{0.972}{0.00018\times 3\times 3600}=0.5,A $
BETA
