Current Electricity Charging Discharging Of Capacitors Question 712
Question: A primary cell has an e.m.f. of 1.5 volt. When short-circuited it gives a current of 3 ampere. The internal resistance of the cell is
Options:
A) 4.5 ohm
B) 2 ohm
C) 0.5 ohm
D) (1/4.5) ohm
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ r=E/I=1.5/3=0.5ohm. $