Current Electricity Charging Discharging Of Capacitors Question 712

Question: A primary cell has an e.m.f. of 1.5 volt. When short-circuited it gives a current of 3 ampere. The internal resistance of the cell is

Options:

A) 4.5 ohm

B) 2 ohm

C) 0.5 ohm

D) (1/4.5) ohm

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $ r=E/I=1.5/3=0.5ohm. $



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