Current Electricity Charging Discharging Of Capacitors Question 724
Question: Two batteries of emf 4 V and 8 V with internal resistance $ 1\Omega $ and $ 2\Omega $ are connected in a circuit with a resistance of $ 9\Omega $ as shown in figure. The current and potential difference between the points P and Q are
Options:
A) $ \frac{1}{3}A $ and 3 V
B) $ \frac{1}{6}A $ and 4 V
C) $ \frac{1}{9}A $ and 9 V
D) $ \frac{1}{12}A $ and 12 V
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ I=\frac{8-4}{1+2+9}=\frac{4}{12}=\frac{1}{3}A; $
$ V _{P}-V _{Q}=4-\frac{1}{3}\times 3=3volt $
BETA
