Current Electricity Charging Discharging Of Capacitors Question 104
Question: For copper-iron (Cu-Fe) couple, the thermo e.m.f. (temperature of cold junction $ =0{}^\circ C $ ) is given by $ E=(14\theta -0.02{{\theta }^{2}})\mu V $ . The neutral temperature will be
Options:
A) $ 350{}^\circ C $
B) 350 K
C) $ 560{}^\circ C $
D) 560 K
Show Answer
Answer:
Correct Answer: A
Solution:
Comparing the given equation with standard equation $ E=\alpha t+\frac{1}{2}\beta ,t^{2}, $ we get $ \alpha =14 $ and $ \frac{1}{2}\beta =-,0.02 $
Therefore b = ? 0.04 Hence neutral temperature $ t _{n}=,-,\frac{\alpha }{\beta } $
$ =,-,\frac{14}{-,0.04}=350{}^\circ C $
BETA
