Current Electricity Charging Discharging Of Capacitors Question 161
Question: The current in a conductor varies with time t as $ I=2t+3t^{2} $ where I is in ampere and t in seconds. Electric charge flowing through a section of the conductor during t = 2 sec to t = 3 sec is
[Orissa JEE 2003]
Options:
A) 10 C
B) 24 C
C) 33 C
D) 44 C
Show Answer
Answer:
Correct Answer: B
Solution:
dQ = $ Idt $
Therefore $ Q=\int _{t=2}^{t=3}{,Idt}= $
$ [ 2\int\limits _{2}^{3}{tdt}+3\int\limits _{2}^{3}{t^{2}dt} ] $ = $ (t^{2} _{2})^3+(t^{3} _{2})^3 $ = (9 ? 4) + (27 ? 8) = 5 + 19 = 24C.
BETA
