Current Electricity Charging Discharging Of Capacitors Question 162
Question: A group of N cells whose emf varies directly with the internal resistance as per the equation EN = 1.5 rN are connected as shown in the figure below. The current I in the circuit is
[KCET 2003]
Options:
A) 0.51 amp
B) 5.1 amp
C) 0.15 amp
D) 1.5 amp
Show Answer
Answer:
Correct Answer: D
Solution:
$ i=\frac{E _{1}+E _{2}+E _{3}+…..+E _{n}}{(r _{1}+r _{2}+r _{3}+…….+r _{n})} $
$ =\frac{1.5(r _{1}+r _{2}+r _{3}+……+r _{n})}{(r _{1}+r _{2}+r _{3}+…..+r _{n})}=1.5A $ .
BETA
