Current Electricity Charging Discharging Of Capacitors Question 738
Question: The resistance of the four arms P, Q, R and S in a Wheatstone’s bridge are 10 ohm, 30 ohm, 30 ohm and 90 ohm, respectively. The e.m.f. and internal resistance of the cell are 7 volt and 5 ohm respectively. If the galvanometer. If the galvanometer resistance is 50 ohm, the current drawn from the cell will be
Options:
A) 0.2 A
B) 0.1 A
C) 2.0 A
D) 1.0 A
Show Answer
Answer:
Correct Answer: A
Solution:
Given : $ V=7V, $ and $ r=5\Omega $
$ R _{eq}=\frac{40\times 120}{40+120}\Omega $
$ I=\frac{V}{R}=\frac{7}{5+\frac{40\times 120}{40+120}}=0.2A. $
BETA
