Current Electricity Charging Discharging Of Capacitors Question 739
Question: In a Wheatstone’s bridge, three resistance P, Q and R connected in the three arms and the fourth arm is formed by two resistances $ S _{1} $ and $ S _{2} $ connected in parallel. The condition for the bridge to be balanced will be
Options:
A) $ \frac{P}{Q}=\frac{2R}{S _{1}+S _{2}} $
B) $ \frac{P}{Q}=\frac{R( S _{1}+S _{2} )}{S _{1}S _{2}} $
C) $ \frac{P}{Q}=\frac{R( S _{1}+S _{2} )}{2S _{1}S _{2}} $
D) $ \frac{P}{Q}=\frac{R}{S _{1}+S _{2}} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ \frac{P}{Q}=\frac{R}{S}\text{ where }S=\frac{S _{1}S _{2}}{S _{1}+S _{2}} $
BETA
