Current Electricity Charging Discharging Of Capacitors Question 740
Question: 125 cm of potentiometer wire balances the emf of a cell and 100 cm of the wire is required for balance, if the poles of the cell are joined by $ 2\Omega $ resistor. Then the internal resistance of the cell is
Options:
A) $ 0.25\Omega $
B) $ 0.5\Omega $
C) $ 0.75\Omega $
D) $ 1.25\Omega $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ r=\frac{{\ell _{1}}-{\ell _{2}}}{{\ell _{2}}}\times R\Omega $ Here, $ {\ell _{1}}=125cm,{\ell _{2}}=100cm,R=2\Omega . $
$ \
Therefore r=0.5\Omega $
BETA
