Current Electricity Charging Discharging Of Capacitors Question 744
Question: A potentiometer arrangement is shown in fig. The driver cell has emf e and internal resistance r. The resistance of potentiometer wire AB is R. F is the cell of em e/3 and internal resistance r/3. Balance point (J) can be obtained for all finite values of
Options:
A) R>r/2
B) R<r/2
C) R>r/3
D) R<r/3
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Current in $ AB=I=\frac{e}{R+r} $ potential difference across $
$ To obtain balanced point, $ \frac{eR}{R+r}>\frac{e}{3}\text{ or }R>r/2 $
BETA
