Current Electricity Charging Discharging Of Capacitors Question 746
A battery of emf $ E _{0}=6V $ is connected across a 2m long uniform wire having resistance $ 4\Omega /m. $ The cells of small emf $ {\varepsilon _{1}}=2V $ and $ {\varepsilon _{2}}=3V $ having internal resistance $ 2\Omega $ and $ 1\Omega $ respectively are connected as shown in the figure. The null point will be obtained at
Options:
A) 0.10m
B) 0.25m
C) 0.50m
D) 0.75m
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Answer:
Correct Answer: D
Solution:
Effective emf of two cells in parallel $ \varepsilon =\frac{{\varepsilon _{1}}r _{2}-{\varepsilon _{2}}r _{1}}{r _{1}+r _{2}}=\frac{3\times 2-2\times 1}{2+1}=\frac{4}{3}V $ X terminal of the connection is positive. For neutral point, positive terminal of $ {\varepsilon _{0}} $ must be connected to X.
BETA
