Current Electricity Charging Discharging Of Capacitors Question 764
Question: The e.m.f. in a thermoelectric circuit with one junction at $ 0{}^\circ C $ and the other at $ t{}^\circ C $ is given by $ E=At-Bt^{2} $ . The neutral temperature is then
[AMU 1995; BCECE 2004]
Options:
A) $ \frac{A}{B} $
B) $ -\frac{A}{2B} $
C) $ -\frac{B}{2A} $
D) $ \frac{A}{2B} $
Show Answer
Answer:
Correct Answer: D
Solution:
At neutral temperature E is maximum so $ \frac{dE}{dt}=0 $
Therefore $ \frac{d}{dt}(At-Bt^{2})=0 $
Therefore $ A-2Bt=0 $
Therefore $ t=\frac{A}{2B} $
BETA
