Current Electricity Charging Discharging Of Capacitors Question 765
Question: The temperature of cold junction and neutral temperature of a thermocouple are $ 15^{o}C $ and $ 280^{o}C $ respectively. The temperature of inversion is
[AMU (Engg.) 1999]
Options:
A) $ 295^{o}C $
B) $ 265^{o}C $
C) $ 545^{o}C $
D) $ 575^{o}C $
Show Answer
Answer:
Correct Answer: C
Solution:
$ t _{n}=\frac{t _{1}+t _{c}}{2} $
Therefore $ 280=\frac{t _{i}+15}{2} $
Therefore $ t _{i}=545^{\circ}C $
BETA
