Current Electricity Charging Discharging Of Capacitors Question 769
Question: For a thermocouple the neutral temperature is $ 270^{o}C $ when its cold junction is at $ 20^{o}C $ . What will be the neutral temperature and the temperature of inversion when the temperature of cold junction is increased to $ 40^{o}C $
[Kerala PET 2001]
Options:
A) $ 290^{o}C,,,580^{o}C $
B) $ 270^{o}C,,,580^{o}C $
C) $ 270^{o}C,,,500^{o}C $
D) $ 290^{o}C,,,540^{o}C $
Show Answer
Answer:
Correct Answer: C
Solution:
No change in neutral temperature but temperature of inversion is $ t _{i}=2t _{n}-t _{c} $
Therefore $ t _{i}=2\times 270-40=500^{o}C $
BETA
