Current Electricity Charging Discharging Of Capacitors Question 772
Question: If $ E=at+bt^{2}, $ what is the temperature of inversion
[DCE 2003]
Options:
A) $ -\frac{a}{2b} $
B) $ +\frac{a}{2b} $
C) $ -\frac{a}{b} $
D) $ +\frac{a}{b} $
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Answer:
Correct Answer: A
Solution:
$ E=at+bt^{2} $ at inversion temperature E will be minimum Thus $ \frac{dE}{dt}=0 $
Therefore $ \frac{d}{dt}[at+bt^{2}]=0 $
Therefore $ a+2bt=0 $
Therefore $ t=-\frac{a}{2b} $
BETA
