Current Electricity Charging Discharging Of Capacitors Question 166
Question: A battery of internal resistance 4W is connected to the network of resistances as shown. In order to give the maximum power to the network, the value of R (in $ \Omega $ ) should be
[IIT 1995]
Options:
A) 4/9
B) 8/9
C) 2
D) 18
Show Answer
Answer:
Correct Answer: C
Solution:
The equivalent network is Clearly, the network of resistances is a balanced Wheatstone bridge. So $ R _{AB} $ is given by $ \frac{1}{R _{AB}}=\frac{1}{3R}+\frac{1}{6R}=\frac{2+1}{6R}=\frac{1}{2R} $
Therefore $ R _{AB}=2R $ For maximum power transfer $ 2R=4\Omega $
Therefore $ R=\frac{4}{2}=2\Omega $
BETA
