Current Electricity Charging Discharging Of Capacitors Question 774
Question: $ e=\alpha ,t-\frac{1}{2}\beta ,t^{2} $ , If temperature of cold junction is $ 0^{o}C $ then temperature of inversion is $ (\text{if }\alpha =500.0\mu V/{{}^{o}}C,,\beta =5.0\mu V/\text{Squar}{{\text{e}}^{o}}C $ )
[DCE 2001]
Options:
A) 100
B) 200
C) 300
D) 400
Show Answer
Answer:
Correct Answer: B
Solution:
$ t _{n}=\frac{\alpha }{\beta }=( \frac{500}{5} )=100{}^\circ C $ Also $ t _{n}=\frac{t _{i}+t _{c}}{2}\Rightarrow 100=\frac{t _{i}+0}{2} $
Therefore $ t _{i}=200{}^\circ C $
BETA
