Current Electricity Charging Discharging Of Capacitors Question 775
Question: If the emf of a thermocouple, one junction of which is kept 0°C is given by $ e=at+1/2,,bt^{2} $ then the neutral temperature will be
[J & K CET 2005]
Options:
A) a/b
B) ? a/b
C) a/2b
D) ?1/ ab
Show Answer
Answer:
Correct Answer: B
Solution:
At neutral temperature, thermal emf will be maximum.
$ \
Therefore ,,\frac{de}{dt}=a+bt $ For maximum or minima, $ a+bt _{n}=0 $
$ \
Therefore ,,,t _{n}=-a/b $
BETA
