Current Electricity Charging Discharging Of Capacitors Question 78
Question: How much current should be passed through acidified water for 100 s to liberate 0.224 litre of $ H _{2} $
[DCE 2002]
Options:
A) 22.4 A
B) $ 19.3A $
C) 9.65 A
D) 1 A
Show Answer
Answer:
Correct Answer: B
Solution:
22.4 litre H2 = 1 mole H2 = N molecules of H2 = 2N atom of H So charge required to liberate 22.4 litre of H2 = 2Ne = 2F Hence charge required to liberate 0.224 litre of H2 $ =\frac{2F}{22.4}\times 0.224 $
$ =\frac{2F}{100}=2\times 965,C $ So current $ i=\frac{Q}{t}=\frac{2\times 965}{100}=19.3,amp $
BETA
