Current Electricity Charging Discharging Of Capacitors Question 246
Question: A galvanometer having a resistance of 8 ohm is shunted by a wire of resistance 2 ohm. If the total current is 1 amp, the part of it passing through the shunt will be
[CBSE PMT 1998]
Options:
A) 0.25 amp
B) 0.8 amp
C) 0.2 amp
D) 0.5 amp
Show Answer
Answer:
Correct Answer: B
Solution:
$ i _{g}S=(i-i _{g})G $
Therefore $ i _{g}(S+G)=iG $
Therefore $ \frac{i _{g}}{i}=\frac{G}{S+G}=\frac{8}{2+8}=0.8 $
BETA
