Current Electricity Charging Discharging Of Capacitors Question 84
Question: Two voltameters, one of copper and another of silver, are joined in parallel. When a total charge q flows through the voltameters, equal amount of metals are deposited. If the electrochemical equivalents of copper and silver are $ z _{1} $ and $ z _{2} $ respectively the charge which flows through the silver voltameter is
[AIEEE 2005]
Options:
A) $ q\frac{z _{1}}{z _{2}} $
B) $ q\frac{z _{2}}{z _{1}} $
C) $ \frac{q}{1+\frac{z _{1}}{z _{2}}} $
D) $ \frac{q}{1+\frac{z _{2}}{z _{1}}} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ m=zq $
Therefore $ z\propto \frac{1}{q} $
Therefore $ \frac{z _{1}}{z _{2}}=\frac{q _{2}}{q _{1}} $ ……(i) also $ q=q _{1}+q _{2} $
Therefore $ \frac{q}{q _{2}}=\frac{q _{1}}{q _{2}}+1 $
Therefore $ q _{2}=\frac{q}{1+\frac{q _{1}}{q _{2}}} $ ……(ii) From equation (i) and (ii) $ q _{2}=\frac{q}{1+\frac{z _{2}}{z _{1}}} $
BETA
