Current Electricity Charging Discharging Of Capacitors Question 171
Question: As the switch S is closed in the circuit shown in figure, current passed through it is
Options:
A) 4.5 A
B) 6.0 A
C) 3.0 A
D) Zero
Show Answer
Answer:
Correct Answer: A
Solution:
Let V be the potential of the junction as shown in figure. Applying junction law, we have or $ \frac{20-V}{2}+\frac{5-V}{4}=\frac{V-0}{2} $ or 40 ? 2V + 5 ? V = 2V or 5V = 45
Therefore V = 9V \ $ i _{3}=\frac{V}{2}=4.5A $
BETA
