Current Electricity Charging Discharging Of Capacitors Question 172
Question: In the following circuit a 10 m long potentiometer wire with resistance 1.2 ohm/m, a resistance R1 and an accumulator of emf 2 V are connected in series. When the emf of thermocouple is 2.4 mV then the deflection in galvanometer is zero. The current supplied by the accumulator will be
Options:
A) 4 ´ 10?4 A
B) 8 ´ 10?4 A
C) 4 ´ 10?3 A
D) 8 ´ 10?3 A
Show Answer
Answer:
Correct Answer: A
Solution:
$ E=x,l=i\rho ,l $
Therefore $ i=\frac{E}{\rho l}=\frac{E}{\rho l}=\frac{2.4\times {{10}^{-3}}}{1.2\times 5}=4\times {{10}^{-4}}A $ .
BETA
