Current Electricity Charging Discharging Of Capacitors Question 183
Question: The reading of the ideal voltmeter in the adjoining diagram will be
Options:
A) 4 V
B) 8 V
C) 12 V
D) 14 V
Show Answer
Answer:
Correct Answer: B
Solution:
Current flowing in the circuit $ i=\frac{E}{R}=\frac{10-4}{20+10}=\frac{1}{5}A $ P.D. across AC $ =\frac{1}{5}\times 20=4V $ P.D. across AN = 4 + 4 = 8V
BETA
