Current Electricity Charging Discharging Of Capacitors Question 113
Question: Resistance of a voltameter is $ 2,\Omega , $ it is connected in series to a battery of 10 V through a resistance of $ 3,\Omega $ . In a certain time mass deposited on cathode is 1 gm. Now the voltameter and the $ 3,\Omega $ resistance are connected in parallel with the battery. Increase in the deposited mass on cathode in the same time will be
Options:
0
B) 1.5 gm
C) 2.5 gm
D) 2 gm
Show Answer
Answer:
Correct Answer: B
Solution:
Remember mass of the metal deposited on cathode depends on the current through the voltameter and not on the current supplied by the battery. Hence by using $ m=Zit, $ we can say $ \frac{m _{Parallel}}{m _{Series}}=\frac{i _{Parallel}}{i _{Series}} $
Therefore $ m _{Parallel}=\frac{5}{2}\times 1=2.5\text{gm}. $ Hence increase in mass = 2.5 - 1 = 1.5 gm
BETA
