Current Electricity Charging Discharging Of Capacitors Question 114
Question: A current of 1.5 A flows through a copper voltameter. The thickness of copper deposited on the electrode surface of area $ 50,cm^{2} $ in 20 minutes will be (Density of copper = 9000 $ kg/m^{3} $ and E.C.E. of copper = 0.00033 g/C)
Options:
A) $ 2.6\times {{10}^{-5}}m $
B) $ 2.6\times {{10}^{-4}}m $
C) $ 1.3\times {{10}^{-5}}m $
D) $ 1.3\times {{10}^{-4}}m $
Show Answer
Answer:
Correct Answer: C
Solution:
Mass deposited $ m=\text{Density}\times \text{Volume}\text{of}\text{the}\text{metal} $
Therefore $ m=\rho \times Ax $ . Also $ m=Zit, $ so $ Zit=\rho Ax $
Therefore $ x=\frac{Zi,t}{A\rho } $
$ =\frac{0.00033\times {{10}^{-3}}\times 1.5\times 20\times 60}{(50\times {{10}^{-4}})\times 9000}=1.3\times {{10}^{-5}},m $
BETA
